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## Homework Statement

if the tangent at a point P("theta") on the ellipse

16 (x^2) + 11 (y^2) = 256

(x^2) + (y^2) + 2(x) = 15

**2. The attempt at a solution**

{{{{ i have taken "theta" as "d" }}}}

P [4 cos d , (16/(sqrt11)) sin d]

equation of tangent at P on ellipse is {(cos d) / 4] x + [(sin d) / (16/(sqrt11))] y = 1 .....(i)

centre of given circle C(-1,0) and radius r = 4

for (i) to also be tangent on the circle - perpendicular distance of (i) from C must be equal to 4

but when i tried to do so i could not get the answer

may be I am doing something wrong so please anyone could guide me the correct way