Taylor development I don't understand

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Homework Statement



Hi everybody! In the middle of an exercise, our teacher suddenly wrote:

<br /> sin(\frac{x}{y} sin y) = \frac{x}{y} sin y - \frac{1}{2} sin θ (\frac{x}{y} sin y)^2<br />

I don't get where does that come from? The closest I've managed to reach is:

<br /> sin(\frac{x}{y} sin y) = \frac{x}{y} sin y - (\frac{x}{y} sin y)^2 \frac{x sin y}{6y} + O(x^5)<br />

What is this θ? It doesn't show up neither before nor after that line :/Thanks in advance for your answers.Julien.
 
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JulienB said:

Homework Statement



Hi everybody! In the middle of an exercise, our teacher suddenly wrote:

<br /> sin(\frac{x}{y} sin y) = \frac{x}{y} sin y - \frac{1}{2} sin θ (\frac{x}{y} sin y)^2<br />

I don't get where does that come from? The closest I've managed to reach is:

<br /> sin(\frac{x}{y} sin y) = \frac{x}{y} sin y - (\frac{x}{y} sin y)^2 \frac{x sin y}{6y} + O(x^5)<br />

What is this θ? It doesn't show up neither before nor after that line :/Thanks in advance for your answers.Julien.

When using TeX/LaTeX, please try to remember to use "\sin" instead of "sin", because using "sin" looks ugly and hard to read, like this ##sin x##, while using "\sin" produced pleasing and easy-to-read results like this: ##\sin x##. Same for cos, tan, csc, sec, cot, (plus their inverses), exp, sinh, cosh, tanh, log, ln, lim, max, min---basically, all the standard functions.

Anyway, he/she is using the standard form of remainder in a Taylor series:
f(x) = f(a) + (x-a) f&#039;(a) + \int_a^x f&#039;&#039;(t) (x-t) \, dt
If ##f''## does not change sign in ##[a,x]## the last term can be expressed as
\frac{1}{2!} (x-a)^2 f&#039;&#039;(\theta), \; \theta \in [a,x]
using the Mean Value Theorem.
 
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There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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