Taylor Series and Maclaurin Series Help

Complexity
Messages
14
Reaction score
0

Homework Statement



http://img704.imageshack.us/f/helpppp.png/

Homework Equations





The Attempt at a Solution



I know e^(x) = 1 + x + x^(2)/2! + ...

But if you multiply that by (x^(4))+4x^(3))

How do you know what bn and a is?
 
Physics news on Phys.org
Complexity said:

Homework Statement



http://img704.imageshack.us/f/helpppp.png/

Homework Equations





The Attempt at a Solution



I know e^(x) = 1 + x + x^(2)/2! + ...

But if you multiply that by (x^(4))+4x^(3))

How do you know what bn and a is?

You have the Maclaurin series for e^x. Just multiply each term by x^4 + 4x^3. That will be the series you're looking for.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
Back
Top