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## Homework Statement

I am trying to find the Tn(x) for sqrt[x] centered at a=1

## Homework Equations

## The Attempt at a Solution

right now i have

f'(x)=1/2x^-1/2

f''(x)=-1/4x^-3/2

f'''(x)=3/8x^-5/2

f''''(x)=-15/16x^-7/2

f'(1)=1/2

f''(1)=-1/4

f'''(1)=3/8

f''''(1)=-15/16

how do i find the coefficient for the nth term?? i keep getting stuck

i tried n/2+1/(-2)^n.. doesn't work

or 1/(-2)^n*(n/2-1)....fail

help please