Temperature Stresses on Unrestrained Cube

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Discussion Overview

The discussion revolves around the volumetric strain of an unrestrained cube subjected to a temperature increase of 1°C. Participants explore the implications of thermal expansion in the context of material mechanics, specifically addressing the relationship between temperature changes and strain when no external restraints are applied.

Discussion Character

  • Technical explanation
  • Debate/contested
  • Mathematical reasoning

Main Points Raised

  • One participant calculates the volumetric strain as 3α, suggesting that thermal expansion leads to this value.
  • The same participant questions the validity of this result, arguing that since the cube is unrestrained, there should be no stresses, leading to a volumetric strain of zero according to the equation εv=(σx +σy+σz)(1-2μ)/E.
  • Another participant points out that the equation referenced by the first participant presupposes the presence of applied stresses, implying a need for modification when considering thermal effects.
  • A further response suggests a modified equation that incorporates thermal expansion effects, indicating that the original strain equations must be adjusted to account for temperature changes.

Areas of Agreement / Disagreement

Participants express differing views on the relationship between thermal expansion and volumetric strain in an unrestrained cube. There is no consensus on whether the volumetric strain should be considered as 3α or zero, and the discussion remains unresolved regarding the appropriate application of the equations involved.

Contextual Notes

The discussion highlights potential limitations in the assumptions made regarding the application of Hooke's law and the effects of thermal expansion, as well as the dependency on the definitions of stress and strain in this context.

Vatsy
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Hii all..

I have a question.Suppose there is a cube of side 1m .It is heated by 1°C. The cube is not restrained in any direction. We are required to find out the volumetric strain.

I am getting it as 3α.

But my question is that since the cube is not restrained , ∴ there should be no stresses in any direction.
∴ εv=(σxyz)(1-2μ)/E
which gives εv=0.

please help..
 
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Vatsy said:
Hii all..

I have a question.Suppose there is a cube of side 1m .It is heated by 1°C. The cube is not restrained in any direction. We are required to find out the volumetric strain.

I am getting it as 3α.

But my question is that since the cube is not restrained , ∴ there should be no stresses in any direction.
∴ εv=(σxyz)(1-2μ)/E
which gives εv=0.

please help..

The equation you quote for the strain pre-supposes that there are applied stresses on the object.
 
Vatsy said:
Hii all..

I have a question.Suppose there is a cube of side 1m .It is heated by 1°C. The cube is not restrained in any direction. We are required to find out the volumetric strain.

I am getting it as 3α.

But my question is that since the cube is not restrained , ∴ there should be no stresses in any direction.
∴ εv=(σxyz)(1-2μ)/E
which gives εv=0.

please help..

Hi Vasty. Welcome to Physics Forums.
Your equation needs to be modified when thermal expansion and contraction effects are involved, as follows:
[tex](ε_v-3αΔT)=\frac{(σ_x+σ_y+σ_z)(1-2μ)}{E}[/tex]
Now, can you figure out how the 6 Hooke's law strain equations have to be modified when thermal expansion effects are included?
 
Chestermiller said:
Hi Vasty. Welcome to Physics Forums.
Your equation needs to be modified when thermal expansion and contraction effects are involved, as follows:
[tex](ε_v-3αΔT)=\frac{(σ_x+σ_y+σ_z)(1-2μ)}{E}[/tex]
Now, can you figure out how the 6 Hooke's law strain equations have to be modified when thermal expansion effects are included?
Thanks a lot... :smile:
 

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