Tension and fluid type question

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To determine the tension in the cable when the spherical hollow steel shell is fully submerged in water, the weight of the shell and its contents, which is 7.2 x 10^5 N, must be considered alongside the buoyant force acting on it. The buoyant force can be calculated using the volume of the sphere and the density of water. The tension in the cable is then found by subtracting the buoyant force from the weight of the shell. Without an instructor, the poster seeks assistance in solving this problem, emphasizing the need for clarity in understanding the physics involved. The discussion highlights the challenges faced in online learning environments.
WhatTheBleepDoIKnow
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I would appreciate any help I could get with this problem...

A spherical-shaped hollow steel shell, with a radius of 2.5m, containing some instruments, is lowered by a cable into a lake. The shell with its contents weighs 7.2 x 10 to the 5th N on the deck of a ship from which it is being lowered. What is the tension in the cable when the sphere is completely immersed in the water?

thanks
 
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have you tried this problem yourself
 
uhh...yes...this is an online class and I have no instructor here to help me all i have in my crappy book
 
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
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