Tension and Torque homework challenge problem.

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Homework Help Overview

The problem involves a system of two masses connected by a cord over a pulley, focusing on the concepts of tension and torque. The scenario includes a 4 kg mass and a 3 kg mass, with a pulley that has a specified moment of inertia and radius. The original poster seeks to determine the acceleration of the masses and the tensions in the cord.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • The original poster attempts to apply equations related to tension and torque to find the acceleration and tensions in the system. Some participants question the necessity of calculating the mass of the pulley, suggesting that only the moment of inertia is needed. Others point out potential inaccuracies in the original poster's understanding of rotational inertia.

Discussion Status

The discussion includes validation of the original poster's calculations by some participants, while others provide critical feedback on specific steps taken. There is acknowledgment of correct answers, but also a focus on clarifying certain assumptions and calculations without reaching a definitive consensus on the overall approach.

Contextual Notes

Participants are operating under the constraints of a homework assignment, with an emphasis on ensuring understanding and correctness in preparation for an upcoming test. There is a noted absence of answers in the textbook for this particular problem.

Tlocc
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Homework Statement


A 4KG mass is connected by a weightless cord to a 3 kg mass on a smooth surface. The pully rotates about a frictionless axle and has a moment of inertia of 0.5 kgm^2 and radius of 0.3m. Assuming that the cord does not slip on the pully, find a.) the acceleration of the two masses and b.) the tensions T1 and T2.


Click the image below to expand it to see what this looks like.

http://img98.imageshack.us/img98/1032/47770145rn2.th.png


Homework Equations


T1=39.24-ma
T2=3a
Torque1=0.3T1
Torque2=0.3T2
I=mr^2
Torque=Parallel force x radius
Net Torque=Ialpha


The Attempt at a Solution



I started by finding the mass(M) of the pully.
0.5=0.09M
M=5.56
I then used the net torque equation, substituting a/r for alpha.
nettorque=1.67a
I then summed my torques to this.
torque1-torque2=1.67a
0.3T1-0.3T2=1.67a
0.3(T1-T2)=1.67a
T1-T2=5.56a
Next I substituted my tensions in.
(39.24-4a)-3a=5.56a
39.24=12.56a
3.12a

I figured that now I could substitute the acceleration back in my original tension equations to find the tensions.
T2=3(3.12)
T2=9.37
T1=39.24-12.48
T1=26.76

There is no answer in the back of the book for this one, and I want somebody to check(rather than skim) my work and tell me if I have come to the right conclusion. If not, please tell me what I have done wrong. It's important that I can do this kind of equation for this week's test.
 
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Looks good to me except for this first step:
Tlocc said:
I started by finding the mass(M) of the pully.
0.5=0.09M
M=5.56
(1) You don't need the mass of the pulley, only the rotational inertia, which is given.
(2) Your equation for rotational inertia (I = mR^2) is incorrect; if you model the pulley as a uniform disk, I = 1/2mR^2.

Luckily, you made no further use of this calculation, so the rest of your work is fine.
 
Your answers are correct.
 
Thanks I'll found out later what the verdict is.
 
I was the only one in the class who got it right. Thanks for checking my work guys X)
 

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