Tension of a rope holing a mass on an inclined plane

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SUMMARY

The discussion focuses on calculating the tension in a string connecting two blocks on a frictionless inclined plane, with masses M1 = 52.0 kg and M2 = 30.0 kg at an angle of q = 11°. The user initially applies Newton's second law (f=ma) but incorrectly combines forces, leading to confusion about the system's configuration. Clarification is sought regarding the orientation of the masses, specifically whether they are hanging or lying on the incline, which is crucial for accurate tension calculation.

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  • Understanding of Newton's second law (f=ma)
  • Knowledge of free-body diagrams
  • Familiarity with inclined plane physics
  • Basic trigonometry, particularly tangent functions
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  • Learn how to draw and analyze free-body diagrams for inclined planes
  • Explore the effects of angles on force components in physics
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Two blocks are connected by a massless string and are held in position by another massless string along a frictionless incline (as shown in the figure). Let M1 = 52.0 kg, M2 = 30.0 kg, and q = 11°. Calculate the tension in the string connecting the two blocks.


so..first i am going to use f=ma

the forces that need to be taken into acount is the weight and noraml force..so i have Fn+w=ma, but the boxes are stationary so the a=0

then i have Fn+w=0...so w=mg so now i have Fn+mg=0

i find Fn=-15288 N which is on the y-axis of my free-body diagram and then i try to solve for the x component on the digram using 11 deg and Fn...tan 11deg=15288/x

but that is not the right approch...please help me
 
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Your post is totally unclear:

1. Are your masses HANGING vertically?
2. Are both your masses lying on the incline?
3. Or is one of the masses hanging, the other lying on the incline?
 
both of the masses are conncected by a rope on an inclined plane with a 11 deg agnle from the horizontal ground
 

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