- #1

Rasine

- 208

- 0

so..first i am going to use f=ma

the forces that need to be taken into acount is the weight and noraml force..so i have Fn+w=ma, but the boxes are stationary so the a=0

then i have Fn+w=0...so w=mg so now i have Fn+mg=0

i find Fn=-15288 N which is on the y-axis of my free-body diagram and then i try to solve for the x component on the digram using 11 deg and Fn...tan 11deg=15288/x

but that is not the right approch...please help me