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**[SOLVED] Tension with horizontal kinetic friction**

## Homework Statement

In Figure, block 1 of mass m1 = 1.8 kg and block 2 of mass m2 = 1.3 kg are connected by a string of negligible mass. Block 2 is pushed by force of magnitude 20 N and angle θ = 39°. The coefficient of kinetic friction between each block and the horizontal surface is 0.22. What is the tension in the string?

http://edugen.wiley.com/edugen/courses/crs1650/art/qb/qu/c06/fig06_61new.gif

## Homework Equations

## The Attempt at a Solution

This is what I end up with but its wrong:

20*cos(39)-20*sin(39)*0.22-

1.3*g*0.22-T=1.3*a

and

T-1.8*g*0.22=1.8*a

Solving for T =

a=T/1.8-g*0.22

20*cos(39)-20*sin(39)*0.22-

1.3*g*0.22-T=1.3*(T/1.8-g*0.22)

(20*cos(39)-20*sin(39)*0.22-

1.3*g*0.22+1.3*g*0.22)*1.3/(1/1.8+1)=T

10.7 N