How Do You Calculate Forces on an Inclined Plane with a Frictionless Pulley?

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To solve the problem of two objects connected by a light string over a frictionless pulley on an inclined plane, it's essential to draw Free Body Diagrams (FBD) for both objects. The acceleration of both objects will be the same in magnitude but opposite in direction, as they are connected by the string. The angle of 55 degrees must be incorporated by resolving the forces acting on the objects into components parallel and perpendicular to the incline. This resolution is crucial for accurately calculating the forces and subsequently determining the acceleration, tension in the string, and the speed of each object after two seconds. Understanding these principles is key to solving the problem effectively.
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This is the question I was given a homework assignment:

2) Two objects are connected by a light string that passes over a frictionless pulley. Draw a Free Body Diagram of both objects. If the inclide is frictionless and if m1= 2kg, m2=6kg and angle theta=55 degrees, find:
(a) the accelerations of the objects
(b) the tension in the string
(c) the speed of each object 2 sec after being released from rest.

**my question is: is the acceleration for both objects the same, just different directions?**

how do you incorporate the theta 55 degrees into this question?
 

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Yes, the acceleration will be the same. In these problems, unless stated otherwise, we typically assume the string doesn't stretch.
As for the 55 degree angle, well, think about it. When you draw the FBD, you're going to have some forces that act parallel to the plane, some that act normal to it, and some that are at some angle. You're going to need to resolve them so you have them all following some arbitrary set of axes - you'll need the angle then. Right?

Edit: About the accelerations - reconsider the "opposite directions" thing. It depends partly on how you're defining the directions, but if you pull on one object, which way will the other one move?
 
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