- #1
cscott
- 782
- 1
[tex]v^2 = \frac{mg}{k}(1 - e^{-2ky/m})[/tex]
As [itex]t \rightarrow \infty[/itex] and [itex]y \rightarrow \infty[/itex] we see [itex]TV = \sqrt{mg/k}[/itex]
And below my book reads: "From actual experience we know that a raindrop reaches its limiting velocity in a finite and not an infinite amount of time. This is because other factors also operate to slow the raindrop's velocity."
What are these factors?
As [itex]t \rightarrow \infty[/itex] and [itex]y \rightarrow \infty[/itex] we see [itex]TV = \sqrt{mg/k}[/itex]
And below my book reads: "From actual experience we know that a raindrop reaches its limiting velocity in a finite and not an infinite amount of time. This is because other factors also operate to slow the raindrop's velocity."
What are these factors?
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