Terminal voltage for 2 batteries

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SUMMARY

The discussion focuses on calculating the terminal voltage of two batteries connected in parallel, specifically batteries A and B with e.m.f values of 100V and 95V, and internal resistances of 5 ohms and 3 ohms, respectively. The terminal voltage is determined to be 94.66V, which can be calculated using the current through the 80 ohm resistor connected across the batteries. The current through the resistor is the sum of the currents from both batteries, applying the principle that the voltage remains constant across parallel components.

PREREQUISITES
  • Understanding of Ohm's Law (V = IR)
  • Knowledge of series and parallel circuits
  • Familiarity with Kirchhoff's Current Law
  • Basic concepts of electromotive force (e.m.f) and internal resistance
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  • Calculate the current through each battery using Kirchhoff's laws
  • Explore the effects of varying internal resistance on terminal voltage
  • Learn about the implications of connecting batteries in parallel
  • Investigate real-world applications of parallel battery configurations
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Students studying electrical engineering, physics enthusiasts, and anyone interested in understanding battery configurations and their electrical characteristics.

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Homework Statement



two batteries A and B are connected in parallel, and an 80 ohm resistor is connected across the battery terminals. the e.m.f and the internal resistance of battery A are 100V and 5ohms respectively, and the corresponding values for battery B are 95V and 3ohms respectively.


Homework Equations



find (a) the value and direction of the current in each battery and (b) the terminal voltage

The Attempt at a Solution



I've done part (a) but I'm stuck on part (b). i know the answer is 94.66V from looking at the back of the textbook but how do i get this answer? please help!
 
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From (a) you know the current through the 80 ohm resister, so you can use V = IR to find the voltage on the whole parallel system including the two batteries.
 
oh so is it the current through battery A, B and the resistor, multiplied by the resistor?
 
The current through the resistor is the sum of the two currents from the batteries. That's the "sum of the currents into a node is zero" rule.
 
oh i see. so the terminal voltage is the sum of the 2 currents from the batteries multiplied by the resistor?
 
Right. You are actually calculating the voltage on the resistor, but the batteries have the same voltage because they are connected to the resistor by conductors with essentially zero resistance. No change in voltage along a wire with no resistance.
 

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