(a) Find the terminal voltage of a 12.0-V motorcycle battery having a 0.520 Ω internal resistance, if it is being charged by a current of 11.7 A.
(b) What is the output voltage of the battery charger?
ΔV = ε - IR
Vterminal = ε - IR
The Attempt at a Solution
ΔV = 12 - (11.7*0.52) = 5.916 = Vterminal
This is incorrect. WebAssign also returned this information:
"What is the sign of the current if it is flowing into the positive terminal of the battery? How is terminal voltage related to the internal resistance and battery emf?"
So I made it negative and submitted the response: -5.916
Still wrong. What am I missing?