- #1
PFStudent
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Homework Statement
Hey,
In my physics textbook the derivation for the transverse velocity, [itex]{v_{s}}[/itex] of a sound wave is given as,
[tex]
{v_{s}(x, t)} = {\frac{\partial}{\partial{t}}}{[s(x, t)]}
[/tex]
[tex]
{v_{s}(x, t)} = -{\omega}{A_{s}}sin({kx}-{{\omega}{t}}+{\phi})
[/tex]
Where,
[tex]
{s(x, t)} = {{A_{s}}{cos({kx} - {{\omega}{t}} + {\phi})}}
[/tex]
I think the book made an error because the transverse velocity of the sound wave really should be,
[tex]
{v_{s}(x, t)} = +{\omega}{A_{s}}sin({kx}-{{\omega}{t}}+{\phi})
[/tex]
The reason it comes out to positive is because the partial derivative with respect to [itex]t[/itex] of [itex]cos\theta[/itex], should be [itex]-sin\theta[/itex] and then (by the chain rule) the derivative of [itex]{-}{\omega}{t}[/itex] should be [itex]{-}{\omega}[/itex], therefore the two negatives should cancel each other out.
Resulting in a positive (one) coefficient for the function,
[tex]
{v_{s}(x, t)} = +{\omega}{A_{s}}sin({kx}-{{\omega}{t}}+{\phi})
[/tex]
So is the book wrong then, since they had a negative sign in front of the omega?
Any help is appreciated.
Thanks,
-PFStudent
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