The Change in velocity and direction.

AI Thread Summary
The discussion revolves around calculating the acceleration of a bullet that changes velocity from 40 m/s horizontally to 44.5 m/s at an angle of 26.1 degrees below the horizontal over 2 seconds. The relevant equations include the change in velocity (delta v) and acceleration (a = delta v / time). An attempt to solve the problem using a head-to-tail diagram resulted in an acceleration of 41 m/s², which is questioned by the poster. Clarification and correct calculations are sought to ensure accuracy before an upcoming test. The need for proper understanding and verification of the solution is emphasized.
Gprime
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Homework Statement


What is the acceleration of a bullet that was shot at 40.m/s in the horizontal and then changed to a velocity of 44.5m/s at 26.1* below the horizontal in a time of 2.0 seconds.

Homework Equations



vf-vi= delta v a= delta v / time

The Attempt at a Solution



I have tried to solve using head to tail diagram and i ended up 41m/s2. I am not entirely sure of this answer, and I have a test next morning on this.
 
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That's not correct. Show how you got that result.
 

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