- #1

Sunfire

- 221

- 4

##E_{tot}^2=(pc)^2+(m_0 c^2)^2## works fine for mass ##m_0## moving with relativistic speeds. What if the moving mass has internal energy also (say, heat). Does the energy-momentum relation still apply? What is the expression for the momentum ##p## then?

Because ##p=\gamma m_0 v## is okay, but perhaps only if we consider the case of ##m_0## not having any other energy, but kinetic- and rest- only.

Thanks!