The fundmental thereom of line integrals

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SUMMARY

The discussion focuses on demonstrating that the line integral is independent of the path taken and evaluating the integral along the specified interval (0,1) to (1,2) for the function defined by the integral ∫_C (1 - ye^(-x))dx + e^(-x)dy. Participants confirm that finding a potential function F = (1 - ye^(-x), e^(-x)) is a valid approach, while also suggesting that verifying the curl is zero can serve as an alternative method. Discrepancies in results are attributed to potential errors in the limits of integration.

PREREQUISITES
  • Understanding of line integrals and their properties
  • Familiarity with vector fields and potential functions
  • Knowledge of the curl of a vector field
  • Basic skills in calculus, particularly integration techniques
NEXT STEPS
  • Study the concept of line integrals in vector calculus
  • Learn how to find potential functions for vector fields
  • Explore the properties of curl and its implications for path independence
  • Practice evaluating line integrals using different paths and compare results
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Students and professionals in mathematics, physics, and engineering who are looking to deepen their understanding of line integrals and their applications in vector calculus.

nameVoid
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show that the line integral is indpendant of path and evaluate the integral on interval (0,1),(1,2)
int c 1-ye^{-x}dx+e^{-x}dy

can someone show me the procedure here looks like they just integrated 1-ye^(-x) on x to get 2/e I get a diffrent answer if I integrate e^(-x) on y same interval do I just find a potential function f with F = 1-ye^-x,e^-x
 
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hi nameVoid! :smile:

(have an integral: ∫ and try using the X2 icon just above the Reply box :wink:)
nameVoid said:
show that the line integral is indpendant of path

do I just find a potential function f with F = 1-ye^-x,e^-x

yes, you can either do that (there's a fairly obvious f :wink:),

or you can show that the curl is zero
and evaluate the integral on interval (0,1),(1,2)
int c 1-ye^{-x}dx+e^{-x}dy

can someone show me the procedure here looks like they just integrated 1-ye^(-x) on x to get 2/e I get a diffrent answer if I integrate e^(-x) on y same interval

if you get different answers, you've probably used the wrong limits …

show us your full calculations, and then we'll see what went wrong! :smile:
 

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