The fundmental thereom of line integrals

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nameVoid
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show that the line integral is indpendant of path and evaluate the integral on interval (0,1),(1,2)
int c 1-ye^{-x}dx+e^{-x}dy

can someone show me the procedure here looks like they just integrated 1-ye^(-x) on x to get 2/e I get a diffrent answer if I integrate e^(-x) on y same interval do I just find a potential function f with F = 1-ye^-x,e^-x
 
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hi nameVoid! :smile:

(have an integral: ∫ and try using the X2 icon just above the Reply box :wink:)
nameVoid said:
show that the line integral is indpendant of path
…
do I just find a potential function f with F = 1-ye^-x,e^-x

yes, you can either do that (there's a fairly obvious f :wink:),

or you can show that the curl is zero
and evaluate the integral on interval (0,1),(1,2)
int c 1-ye^{-x}dx+e^{-x}dy

can someone show me the procedure here looks like they just integrated 1-ye^(-x) on x to get 2/e I get a diffrent answer if I integrate e^(-x) on y same interval

if you get different answers, you've probably used the wrong limits …

show us your full calculations, and then we'll see what went wrong! :smile: