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To calculate the X and Y velocities of a body given a force F and angles A(α) and B(β), one can use right-angle trigonometry. By creating a right triangle with F as the hypotenuse, the velocities can be expressed as X velocity = cos(γ) * F and Y velocity = sin(γ) * F, where γ = α - β. A discussion arose regarding the scenario when α = 0 and β = -90, leading to confusion about the resulting velocities. It was clarified that if the force is directed solely in one direction, one component will carry all the force while the other will be zero. The importance of correctly applying vector principles in this context was emphasized.
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Lets say that the body has force F in the direction B(β).
What is the formula that would let me calculate X velocity and Y velocity of the body?
The formula should include all three factors, A(α), B(β), and F (force of the body)

I've encountered this problem while developing computer game. Thanks for help!
~Kustrle
 
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Create a right triangle with F as the hypotenuse and one side being the X Velocity and the other side being the Y velocity. Then if you know the angle of the object, you can use right-angle trig to figure out the other sides.




Sorry about the error in posting, accidentally pressed 'post quick reply' instead of 'go advanced.'
 
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I can only include 1 angle (α) and force in right triangle (other angle will always be 90-α).
 
You only need one angle and one side.
 
For the angle I take γ=α-β
From that I get that X velocity = cosγ*F and Y velocity = sinγ*F
Now let's say that α=0 and β=-90. It's obvious that both X and Y velocities are equal to 0. But from the equations above I get that X velocity = 0 while Y velocity = F which is wrong.
 
No they wouldn't both be zero. If F is only in one direction, one vector will have all of the force and the other will have none.
 
Yes all the force would be in Y direction, but it just couldn't be applied so Y velocity would still be 0.
 
I don't understand what's wrong, if you just use right angle trig I know it will work out, it's basic vectors.
 
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