The proof of convergence. I am confused with the summation

flyingpig
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Homework Statement



Prove\; that\;if\;\sum_{n=1}^{\infty} a_n \;converges,\;then \lim_{n\to\infty}a_n = 0

Book solution

s_n= a_1 + a_2 +...+a_n

s_{n-1}= a_1 + a_2 +...+a_{n-1}

a_n=s_n-s_{n-1}

Then they did a few limits, and proved that the difference is 0. BUt that is not my question.

My question is this part
s_{n-1}= a_1 + a_2 +...+a_{n-1}

If it is n - 1, why are they starting from a1? Shouldn't it be a0/sub]?
 
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No. If we're assuming that the first term in the sum is a_{1}, the (n-1)th partial sum is defined to be s_{n-1}= a_1 + a_2 +...+a_{n-1}, i.e. it's the sum of the first term, the second term, ... , and the (n-1)th term.
 
Yeah exactly so it should be a0
 
In your problem, the first term will always be a_{1}. The partial sum that we choose won't affect the first term. We could have s_{n}, s_{n-1}, s_{n+3}, but in each case the first term will always be a_{1}

If you're still not convinced, take a look at:

http://mathworld.wolfram.com/PartialSum.html

However, if the series defined is given as \sum_{n=0}^{\infty} a_n, then you would be right. The first term of all partial sums would start at a_{0}. It just depends on the first term that's defined.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...

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