The question is: How can I find the magnetic field inside a long conductor?

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SUMMARY

The discussion focuses on calculating the magnetic field inside a long cylindrical conductor using Ampere's Law. The key equation derived is B*2πr = μI_enclosed, where I_enclosed is determined by the current density, which is constant across the conductor's cross-section. The fraction of the current enclosed within a radius r is given by the ratio of the areas, specifically I_enclosed = I_total * (πr²/πa²). This approach simplifies the calculation of the magnetic field inside the conductor.

PREREQUISITES
  • Understanding of Ampere's Law
  • Knowledge of cylindrical symmetry in magnetic fields
  • Familiarity with current density concepts
  • Basic calculus for area calculations
NEXT STEPS
  • Study the application of Ampere's Law in different geometries
  • Learn about magnetic fields in conductors of varying shapes
  • Explore the concept of current density in more detail
  • Investigate the effects of varying current distributions on magnetic fields
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Physics students, electrical engineers, and anyone studying electromagnetism who seeks to understand magnetic fields in conductors.

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Homework Statement


I have to find the magnetic field inside a long conductor of radius a.


Homework Equations


Ampere's law.
∫B.dl=μIenclosed


The Attempt at a Solution



Problem has cylindrical symmetry and B is along θ direction.

B*2∏r=μIenclosed

How to find what fraction of current inside the area considered?

I just saw in a book that it is ∏r2/∏a2.But can't figure out the idea.:(

I know it is very simple and donno why i forget basics always..:(
 
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You have a total current I in the wire. Assume it's evenly distributed across the cross-sectional area of the wire. What would be the current density?
 
Yeah!now got it.
Current density is constant.

Ienc/∏r2= Itotal/∏α2
 

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