mangaroosh said:
Accoridng to Einsteinian relativity, LC & TD are caused by the relative motion of a reference frame; if LC & TD occur then it should mean that c is invariant; using RoS as a reason why that isn't the case is circular reasoning.
Your language here is a little confused, so I am concerned that your thoughts are also a little confused. When we are talking about the different postulates and conclusions in relativity we are not talking about a "cause and effect" effect relationship, but rather a "logical implication" relationship.
A cause and effect relationship involves more than a logical implication relationship, specifically it also implies a temporal ordering where the cause preceeds the effect. There is no such temporal ordering between LC, TD, RoS, the principle of relativity (PoR) and the invariance of c (C), so you cannot speak of causes or effects amongst them.
So, what we have is properly "implies" and not "causes". The proper way to express this formally is:
[itex](\text{PoR} \cap \text{C})\leftrightarrow (\text{LC} \cap \text{TD} \cap \text{RoS})[/itex]
Notice that the relationship is bidirectional (i.e. "if and only if").
If the above statement is true then all of the following statements are true and non-circular:
[itex](\text{PoR} \cap \text{C})\rightarrow (\text{LC} \cap \text{TD} \cap \text{RoS})[/itex]
[itex](\text{PoR} \cap \text{C})\rightarrow (\text{TD} \cap \text{RoS})[/itex]
[itex](\text{PoR} \cap \text{C})\rightarrow (\text{LC} \cap \text{RoS})[/itex]
[itex](\text{PoR} \cap \text{C})\rightarrow (\text{LC} \cap \text{TD})[/itex]
[itex](\text{PoR} \cap \text{C})\rightarrow \text{LC}[/itex]
[itex](\text{PoR} \cap \text{C})\rightarrow \text{TD}[/itex]
[itex](\text{PoR} \cap \text{C})\rightarrow \text{RoS}[/itex]
[itex](\text{LC} \cap \text{TD} \cap \text{RoS})\rightarrow (\text{PoR} \cap \text{C})[/itex]
[itex](\text{LC} \cap \text{TD} \cap \text{RoS})\rightarrow \text{C}[/itex]
[itex](\text{LC} \cap \text{TD} \cap \text{RoS})\rightarrow \text{PoR}[/itex]
As with any iff relationship you can, of course, make circular statements such as [itex](\text{PoR} \cap \text{C})\rightarrow (\text{LC} \cap \text{TD} \cap \text{RoS})\rightarrow \text{C}[/itex]. But that does not imply that either [itex](\text{PoR} \cap \text{C})\rightarrow (\text{LC} \cap \text{TD} \cap \text{RoS})[/itex] or [itex](\text{LC} \cap \text{TD} \cap \text{RoS})\rightarrow \text{C}[/itex] are circular.
This whole conversation began when you correctly pointed out that [itex](\text{LC} \cap \text{TD})\rightarrow \text{C}[/itex] is false. I responded by correctly pointing out that [itex](\text{LC} \cap \text{TD} \cap \text{RoS})\rightarrow \text{C}[/itex] is true and you had neglected RoS which is an essential part of SR. You then followed up with the incorrect assertion that [itex](\text{LC} \cap \text{TD})\rightarrow \text{RoS}[/itex] to which I gave a counter-exmaple. The rest of the conversation has basically been follow-up to that.
I hope this clarifies things.
mangaroosh said:
Is that a transform used in Einsteinian relativity?
No, it is merely a counter example to your claim of post 121 that "LC & TD must occur in order for c to be invariant" i.e. [itex]\text{C}\rightarrow (\text{LC} \cap \text{TD})[/itex]