The work integral (general question)

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The discussion centers on evaluating the work integral W=\int_{s_i}^{s_f} \mathrm{\vec{F}}\cdot\,\mathrm{d}\vec{s}, specifically how to handle vector calculus and line integrals. Participants clarify that the dot product is performed within the integral, focusing on parallel components of the force vector and displacement. It is emphasized that both the force vector and differential displacement can be broken down into their respective components, allowing for easier integration. The conversation highlights the importance of understanding whether the field is scalar or vector, as this affects the calculation method. Ultimately, the integration process involves careful manipulation of these components to achieve the desired scalar result.
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I'm sure you're all familar with this forumla for work, <br /> W=\int_{s_i}^{s_f} \mathrm{\vec{F}}\cdot\,\mathrm{d}\vec{s}<br /> <br />

I don't understand how to evaluate this integral. How do you antidifferentiate in terms of a vector? How do you evaluate the dot product when ds isn't an actual value?

Thanks! :)
 
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It's done with something called vector calculus, more specifically, line integrals.
http://en.wikipedia.org/wiki/Line_integral#Vector_calculus

Depending on whether it's a scalar or vector field, it is calculated slightly differently. Nevertheless, we will do a dot product inside the integral while manipulating the integral into something more familiar, so only parallel components will count.
 
So would we do the dot product of F and delta-s? If so, that would give us a scalar value (or perhaps a function), and what would we integrate that in terms of?
 
Remember that ds can be broken down into components dx and dy just like F can be broken down into components Fx and Fy (Fx and Fy do not represent partial derivatives here).
 
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