(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

The problems are these:

y' + (3y/t) = (Sin(t)/t^3)

ty'-2y = t^3 + t^2, t>0

(general case)

y't^3+(3yt^2), y(2) = 0

(specific case)

2. Relevant equations

Basic ODE solving skills

3. The attempt at a solution

I can't figure out how to make the y's and y''s go on one side, and make the t's go on the other side of the equation. I think there is some completing a square trick or something to solve those.

Now, I did this problem earlier:

y + 3y = te^-3t

and integrated and multiplied both sides by two to get an implicit solution of:

2y+6y^2 = (-2/9)e^-3x (3x+1) + C

Did I do this correctly? As far as I now, all I have to do is integrate both sides (even though I don't see any dy's or dx's, so am confused).

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# There is a series of ODE problems I can't understand

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