1. The problem statement, all variables and given/known data The problems are these: y' + (3y/t) = (Sin(t)/t^3) ty'-2y = t^3 + t^2, t>0 (general case) y't^3+(3yt^2), y(2) = 0 (specific case) 2. Relevant equations Basic ODE solving skills 3. The attempt at a solution I can't figure out how to make the y's and y''s go on one side, and make the t's go on the other side of the equation. I think there is some completing a square trick or something to solve those. Now, I did this problem earlier: y + 3y = te^-3t and integrated and multiplied both sides by two to get an implicit solution of: 2y+6y^2 = (-2/9)e^-3x (3x+1) + C Did I do this correctly? As far as I now, all I have to do is integrate both sides (even though I don't see any dy's or dx's, so am confused).