Thermal conductivity of a metalic bar

Mppl
Messages
12
Reaction score
0

Homework Statement



we have a metalic bar with thermal condutivity of 200w/(m*k) it has an area of 20 cm^2 which is in contact with with an heater that delivers 200 W and is at 300ºC. the metalic bar has a thickness of 1cm

The two questions are:
a) once the system have entered a stationary state what's the temprature of the other of the side of the bar that is not in contact with the heater?
b) calculate the flux going through the metalic bar

Homework Equations





The Attempt at a Solution



well I haven't got far, I know that the flux of heat going to a surface is J=-k*grad(T) and from that I get that there is no flux going out the side walls of the bar.
I also concluded that at the stationary state the side of the bar which is not in contact with the heater won't be at 300ºC for in that case the flux of heat would be zero.
I think that if the board is in contact with something at the other end then it should be always at roam temperature because if it goes above that temperature there will be a discontinuity in the temprerature and it will result in an infinite flux.

Now I don't know what else to do.

Thank you
 
Physics news on Phys.org
You're on the right track. How do you calculate grad(T)? How does this relate the temperature difference across the bar to the heater power?
 
Thread 'Need help understanding this figure on energy levels'
This figure is from "Introduction to Quantum Mechanics" by Griffiths (3rd edition). It is available to download. It is from page 142. I am hoping the usual people on this site will give me a hand understanding what is going on in the figure. After the equation (4.50) it says "It is customary to introduce the principal quantum number, ##n##, which simply orders the allowed energies, starting with 1 for the ground state. (see the figure)" I still don't understand the figure :( Here is...
Thread 'Understanding how to "tack on" the time wiggle factor'
The last problem I posted on QM made it into advanced homework help, that is why I am putting it here. I am sorry for any hassle imposed on the moderators by myself. Part (a) is quite easy. We get $$\sigma_1 = 2\lambda, \mathbf{v}_1 = \begin{pmatrix} 0 \\ 0 \\ 1 \end{pmatrix} \sigma_2 = \lambda, \mathbf{v}_2 = \begin{pmatrix} 1/\sqrt{2} \\ 1/\sqrt{2} \\ 0 \end{pmatrix} \sigma_3 = -\lambda, \mathbf{v}_3 = \begin{pmatrix} 1/\sqrt{2} \\ -1/\sqrt{2} \\ 0 \end{pmatrix} $$ There are two ways...
Back
Top