Thermal expansion of a copper pipe

Click For Summary
SUMMARY

The discussion centers on calculating the minimum volume of a reservoir tank required to accommodate the overflow of water in a hot-water heating system using a 63.1 m copper pipe with an inside radius of 7.69 x 10^-3 m. The volumetric expansion coefficient for copper is given as 51 x 10^-6 /°C. The calculated change in volume of the copper pipe when heated from 20.3 to 60.2 °C is 2.3854 x 10^-5 m³. It is established that the change in volume of water, which expands more than copper, must also be considered to determine the total overflow volume.

PREREQUISITES
  • Understanding of thermal expansion principles
  • Familiarity with volumetric expansion coefficients
  • Basic knowledge of geometry related to cylindrical volumes
  • Ability to perform unit conversions between cubic meters and liters
NEXT STEPS
  • Calculate the change in volume of water using a volumetric coefficient of 0.000214 /°C
  • Learn about the thermal expansion of different materials
  • Research the design specifications for domestic expansion tanks
  • Explore practical applications of thermal expansion in plumbing systems
USEFUL FOR

Engineers, plumbers, and students studying thermodynamics or fluid mechanics who need to understand the implications of thermal expansion in heating systems.

slaw155
Messages
41
Reaction score
0

Homework Statement


Many hot-water heating systems have a reservoir tank connected directly to the pipeline, so as to allow for expansion when the water becomes hot. The heating system of a house has 63.1 m of copper pipe whose inside radius is 7.69 x 10^-3 m. When the water and pipe are heated from 20.3 to 60.2 °C, what must be the minimum volume of the reservoir tank to hold the overflow of water?

Homework Equations


change in volume = initial volume x change in temp x volumetric expansion coefficient
coefficient as provided by teacher = 51 x 10^-6 /degC

The Attempt at a Solution


change in vol = 63.1m^3 x ∏ x (7.69x10^-3)^2 x (60.2-20.3) x 51 x 10^-6 = 2.3854 x 10^-5 m^3
Now would I add this change in volume to the volume of the pipe initially or is this in itself the correct answer?
 
Last edited:
Physics news on Phys.org
You should always include units in your calculations. How else can you tell what these numbers mean?
 
The units are in the question.
 
The expansion vessel only has to accommodate the extra volume.

Domestic models are typically specified in Litres rather than cubic meter. Google them.
 
I think you should calculate change in water volume too, use volumetric coefficient as 0.000214/deg C. initial volume of water is same as copper pipe.
From the values we can understand change in volume of water will be much greater compared to copper , also liquid expands more than solid.
If you subtract the volume change of water - volume change of copper, you will get the overflowing water volume i.e the answer.
 
slaw155 said:
Now would I add this change in volume
You have calculated a change in interior volume of pipe, correct? Is it an increase or a decrease? How does that relate to overflow?
 
You guys realize that this thread is 4 years old, right?
 
  • Like
Likes   Reactions: haruspex
Chestermiller said:
You guys realize that this thread is 4 years old, right?
Ah.
 
If you as the initial volume to the change in volume, it won't change the results. Because initial volume will get added to both water and copper, so they will cancel each other

V initial +chage in V of water =V initial + change in V of copper

Thus, the initial volume will get canceled on each side
 

Similar threads

  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 6 ·
Replies
6
Views
3K
Replies
3
Views
4K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 16 ·
Replies
16
Views
2K
  • · Replies 66 ·
3
Replies
66
Views
4K
  • · Replies 6 ·
Replies
6
Views
3K
  • · Replies 13 ·
Replies
13
Views
7K
  • · Replies 3 ·
Replies
3
Views
2K