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Homework Help: Thermal expansion of a copper pipe

  1. Aug 19, 2014 #1
    1. The problem statement, all variables and given/known data
    Many hot-water heating systems have a reservoir tank connected directly to the pipeline, so as to allow for expansion when the water becomes hot. The heating system of a house has 63.1 m of copper pipe whose inside radius is 7.69 x 10^-3 m. When the water and pipe are heated from 20.3 to 60.2 °C, what must be the minimum volume of the reservoir tank to hold the overflow of water?


    2. Relevant equations
    change in volume = initial volume x change in temp x volumetric expansion coefficient
    coefficient as provided by teacher = 51 x 10^-6 /degC


    3. The attempt at a solution
    change in vol = 63.1m^3 x ∏ x (7.69x10^-3)^2 x (60.2-20.3) x 51 x 10^-6 = 2.3854 x 10^-5 m^3
    Now would I add this change in volume to the volume of the pipe initially or is this in itself the correct answer?
     
    Last edited: Aug 19, 2014
  2. jcsd
  3. Aug 19, 2014 #2

    SteamKing

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    You should always include units in your calculations. How else can you tell what these numbers mean?
     
  4. Aug 19, 2014 #3
    The units are in the question.
     
  5. Aug 19, 2014 #4

    CWatters

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    The expansion vessel only has to accommodate the extra volume.

    Domestic models are typically specified in Litres rather than cubic meter. Google them.
     
  6. Apr 20, 2018 #5
    I think you should calculate change in water volume too, use volumetric coefficient as 0.000214/deg C. initial volume of water is same as copper pipe.
    From the values we can understand change in volume of water will be much greater compared to copper , also liquid expands more than solid.
    If you subtract the volume change of water - volume change of copper, you will get the overflowing water volume i.e the answer.
     
  7. Apr 20, 2018 #6

    haruspex

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    You have calculated a change in interior volume of pipe, correct? Is it an increase or a decrease? How does that relate to overflow?
     
  8. Apr 20, 2018 #7
    You guys realize that this thread is 4 years old, right?
     
  9. Apr 20, 2018 #8

    haruspex

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    Ah.
     
  10. Apr 22, 2018 #9
    If you as the initial volume to the change in volume, it won't change the results. Because initial volume will get added to both water and copper, so they will cancel each other

    V initial +chage in V of water =V initial + change in V of copper

    Thus, the initial volume will get cancelled on each side
     
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