Does Thermal Expansion Affect the Enclosed Volume or the Shell Material Volume?

AI Thread Summary
When a spherical shell is heated, its volume changes according to the equation V(T)=V(0)(1+yT), where y is the volume coefficient of thermal expansion. This volume change applies equally to both the volume of the shell material and the volume it encloses, as both expand by the same fraction. The increase in radii for both the shell and the enclosed cavity will be 'aT', where 'a' is the linear coefficient of thermal expansion, assuming the material is isotropic. Therefore, the expansion behavior is consistent regardless of whether one considers the shell's material or the enclosed volume. Understanding this principle is crucial for applications involving thermal expansion in spherical shells.
miss photon
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[SOLVED] thermal expansion

hi everybody
my question is:
a spherical shell is heated. the volume changes according to the equation V(T)=V(0)(1+yT) where y=volume coeff. of thermal expansion. does this volume refer to the volume enclosed by the shell or the volume of the material making up the shell?
 
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By the shell itself. A spherical shell and a solid one (same dia. and material) should be expanding to the same size.
 
miss photon said:
does this volume refer to the volume enclosed by the shell or the volume of the material making up the shell?
It doesn't matter. All volumes expand by the same fraction, whether you take the volume of the shell material or the volume enclosed by the shell. When the material expands, so does the volume it encloses.
 
let me put it in another way. if the shell of radius R has a spherical cavity of radius r, what will be the change in the two radii on heating? will the increase in both be 'aT' where a=linear coeff of thermal expansion?
 
miss photon said:
will the increase in both be 'aT' where a=linear coeff of thermal expansion?
Yes. Assuming the material is isotropic, all linear dimensions expand by the same fraction.
 
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