1. The problem statement, all variables and given/known data 250.0g of copper at 100.0°C are placed in a cup containing 325.0g of water at 20.0°C. Assume no heat loss to the surroundings. What is the final temperature of the copper and water? 2. Relevant equations Conservation of Energy mcCΔTc = mhCΔTh 3. The attempt at a solution mcCΔTc = mhCΔTh (0.250)(390)(Tf - Ti) = (0.325)(4200)(Tf - Ti) (0.250)(390)(Tf - 100) = (0.325)(4200)(Tf - 20) Have I set up my equation properly?