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## Homework Statement

250.0g of copper at 100.0°C are placed in a cup containing 325.0g of water at 20.0°C. Assume no heat loss to the surroundings. What is the final temperature of the copper and water?

## Homework Equations

Conservation of Energy

m

_{c}CΔT

_{c}= m

_{h}CΔT

_{h}

## The Attempt at a Solution

m

_{c}CΔT

_{c}= m

_{h}CΔT

_{h}

(0.250)(390)(T

_{f}- T

_{i}) = (0.325)(4200)(T

_{f}- T

_{i})

(0.250)(390)(T

_{f}- 100) = (0.325)(4200)(T

_{f - 20})

Have I set up my equation properly?