(Thermal) Vibrational degrees of freedom

argon
Messages
5
Reaction score
0
Let's say I have a molecule such as CO2, where there are three atoms and a linear structure. I understand that there are 3 translational degrees of freedom and 2 rotational degrees of freedom (since it's symmetric). However, the number of vibrational degrees of freedom (DoF) confuses me.

My professor says there are 4 DoF. A quick Google search has people claiming 4.

I think the answer is 8 though. There are 4 vibrational modes (if this is correct) for CO2, and each mode gets a DoF from kinetic energy and one from potential energy. This makes 8.

There are also some websites claiming that for a non-linear molecule, there are 3N-6 vibrational modes and for a linear molecule there are 3N-5 vibrational modes. Some websites call these vibrational degrees of freedom instead, but this terminology is important to distinguish since it changes my answer by a factor of 2. Which is correct?

Assume sufficiently high temperatures for this discussion such that no modes are frozen out.
 
Physics news on Phys.org
Look at DOF in another way... Try to find the minimum number of coordinates you need to know the exact position of CO2 molecule , there are three atoms with each having x,y coordinates. Assume that you know the distance between Carbon And oxygen atoms.
 
Hi, I had an exam and I completely messed up a problem. Especially one part which was necessary for the rest of the problem. Basically, I have a wormhole metric: $$(ds)^2 = -(dt)^2 + (dr)^2 + (r^2 + b^2)( (d\theta)^2 + sin^2 \theta (d\phi)^2 )$$ Where ##b=1## with an orbit only in the equatorial plane. We also know from the question that the orbit must satisfy this relationship: $$\varepsilon = \frac{1}{2} (\frac{dr}{d\tau})^2 + V_{eff}(r)$$ Ultimately, I was tasked to find the initial...
Back
Top