Thermodynamic Changes in Phase Transitions

AI Thread Summary
When water freezes to ice at constant temperature, the internal energy (U) decreases, heat (Q) is released, and work (W) done is negligible. Conversely, when ice melts to water at constant temperature, heat is absorbed (Q > 0), leading to an increase in internal energy (U > 0) while work done remains negligible. For water evaporating at constant temperature, heat is supplied (Q > 0), resulting in an increase in internal energy (U > 0) with negligible work done. During boiling, heat is also supplied (Q > 0), causing an increase in internal energy (U > 0) with negligible work. Overall, the phase transitions involve specific changes in internal energy, heat, and work based on the state changes of water.
kram
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Homework Statement


Does the internal energy increase/decrease(U), quantity of heat released or supplied (Q), and work done by or on a system (W) when
(a) water freezes to ice at constant temperature
(b) ice melts to water at constant temperature
(c) water evaporates at constant temperature
(d) water boils at constant temperature?


Homework Equations


First Law of Thermodynamics
U = Q + W
where U is internal energy of the system, Q is the quantity supplied to the system and W is the work done on the system.
 
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Not sure what the question is. I'm guessing, you are supposed to say whether deltaU, Q, and W is positive or negative or zero in each situation?

To answer the deltaU part, you need to remember that internal energy is a direct function of temperature.
 
Sorry, the question was asking whether deltaU, Q, and W is positive or negative or zero in each situation?

if (a) water freezes to ice at constant temperature,
then delta W = 0 (since work done by atmospheric pressure is negligible as volume change is small), delta Q < 0 (heat energy is released when bonds are formed during freezing) and hence by equation delta U = delta Q + delta W, delta U < 0 , ie internal energy decreases. am i right?

how about the others?
 
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