Thermodynamic Problems: Work and Heat in a Thermodynamic Process

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SUMMARY

The discussion focuses on calculating the work associated with a thermodynamic process involving an ideal gas. Initially, 0.745 moles of gas occupy 3.55 L at 3.82 atm and an internal energy of 1705 J. The gas is cooled at constant volume to a pressure of 2.06 atm, followed by expansion at constant pressure to a volume of 6.65 L, resulting in a final internal energy of 2098 J. The work done during this process is calculated using the formula W = -P * ΔV, with attention to significant figures and the correct interpretation of signs in thermodynamic work.

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yuvlevental
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Homework Statement


Initially, 0.745 moles of an ideal gas in a container occupies a volume of 3.55 L at a pressure of 3.82 atm with an internal energy of 1705 J. The gas is then cooled at a constant volume until its pressure is 2.06 atm. Then the gas is allowed to expand at a constant pressure until its volume is 6.65 L. The final internal energy is 2098 J. Consider the processes to be quasi-static. What is the work associated with this entire process?

Homework Equations


W=-P*deltaV
deltaU=Q + W

The Attempt at a Solution


Is it correct that you take the 2.06, multiply it by 1E5, and multiply the answer by the change in volume in m^3 to find -638.60 J
 
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Yes and no. Your method is correct, but your answer has too many sig figs.
 
yuvlevental said:
What is the work associated with this entire process?
Other than sig figs, the use of prepositions matters. Work done on what by what? I think that there is a sign uncertainty here.
 

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