1. Not finding help here? Sign up for a free 30min tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Thermodynamics: Fan in a room

  1. Sep 22, 2014 #1
    1. The problem statement, all variables and given/known data

    A person living in a 4m x 5m x 5m room turns on a 100-W fan before he leaves a warm room at 100kPa, 30 degrees Celsius, hoping that when he returned in 5 hours, the room would be cooler. Disregarding any heat transfer determine the temperature of the room when he comes back. ( Assume the air to be an ideal gas with molar heat capacity C_v=3R/2).

    2. Relevant equations
    I couldn't get any of the latex code to work in the new website format.

    R=k_B/N_A
    pV=nRT
    deltaU=Q+W

    3. The attempt at a solution

    So I calculated the energy put into the system by the fan and got: E=100(60)(60)= 1,800,000 J

    The volume of the room doesn't change but I know the pressure will increase so therefore the temperature will increase. I'm having trouble finding out how to find this though. Would anyone be able to point me to the next step? Any help is much appreciated.
     
  2. jcsd
  3. Sep 22, 2014 #2
    Since there is no heat transfer into or out of the room, what is delta U? How is deltaU related to the temperature change?

    Chet
     
  4. Sep 23, 2014 #3
    deltaU is 0? Well Q=mCdeltaT, am I on the right track with that?
     
  5. Sep 23, 2014 #4

    Andrew Mason

    User Avatar
    Science Advisor
    Homework Helper

    Delta U = Q + W where W is the work done on the gas. Is any work being done on the gas? (it says to ignore Q). That will tell you what happens to U.

    AM
     
  6. Sep 23, 2014 #5
    No. delta U is not zero. The fan is doing work on the gas. How is delta U related to the work W when Q is zero?
     
  7. Sep 29, 2014 #6
    So deltaU = W then?

    Sorry for the late reply and thanks for all the help!
     
  8. Sep 29, 2014 #7

    mfb

    User Avatar
    2016 Award

    Staff: Mentor

    Don't forget units and the 5 hours on the left side.

    Pressure will be constant - you cannot pressurize a real room, air will escape through various openings.
     
  9. Sep 29, 2014 #8
    Oh I forgot to multiply by 5. So E = 9,000,000 J
     
  10. Sep 29, 2014 #9

    mfb

    User Avatar
    2016 Award

    Staff: Mentor

    No you did not forget it (otherwise your answer would not fit), you just forgot to write it down.
     
  11. Sep 29, 2014 #10
    Yes.
     
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook

Have something to add?
Draft saved Draft deleted



Similar Discussions: Thermodynamics: Fan in a room
  1. Dehumidifying a Room (Replies: 5)

  2. Thermodynamics ! (Replies: 1)

  3. Heating a room (Replies: 10)

  4. Thermodynamics ! (Replies: 1)

  5. Tension in the room (Replies: 3)

Loading...