Thermodynamics - Find initial pressure (given Temperatures)

AI Thread Summary
To determine the initial pressure of R-410a vapor at 20°C in a sealed tube, the discussion highlights the use of thermodynamic tables and the ideal gas equation. The vapor is observed to condense into droplets at -20°C, indicating a saturated state at that temperature. Participants suggest that the vapor pressure at -20°C can be read directly from the thermodynamic tables, which would be approximately 399.6 kPa. The ideal gas law may also be applied, but the focus remains on utilizing the tables for accurate pressure readings. Understanding the relationship between temperature and pressure through these methods is essential for solving the problem.
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1. Homework Statement

For a certain experiment, R-410a vapor is contained in a sealed glass tube at 20°C. It is
desired to know the pressure at this condition, but there is no means of measuring it, since
the tube is sealed. However, if the tube is cooled to −20°C small droplets of liquid are
observed on the glass walls. What is the initial pressure?

2. Homework Equations

Thermodynamic tables
ideal gas equation?

3. The Attempt at a Solution

I set up both states:
State 2: T = -20 (saturated)

State 1: T = 20, v1=v2=0.0648 P = ? (superheated)

I just don't understand how we can figure it out from just the temps. I just can't wrap my mind around the thermodynamic tables.
 
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What happens at -20?
 
At -20, the condensation occurs?
 
Can you use it to find vapor pressure at -20? With the help of tables?
 
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Is it read directly from the table? would it be 399.6 kPa?
 
No idea, I don't have these tables. But yes, you should read it directly from the table.
 
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So, how would I use this information to find the initial pressure?

Could I just use the ideal gas? P1/T1 = P2/T2 ?
 
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