How Much Water Can a Freezer Turn to Ice in One Hour?

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A user inquired about the volume of water a freezer can convert to ice in one hour, given a coefficient of performance of 7.0 and a power input of 1.0 kilowatt. They initially calculated the heat removed (QL) as 700J but were confused about their mass calculation, which resulted in 0.002 kg. After realizing their error in converting kilowatts to joules per second, they corrected their understanding of the energy conversion. The user also sought guidance on how to close the thread, noting that only administrators have that capability. The discussion highlights the importance of accurate unit conversions in thermodynamic calculations.
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1. What volume of water at 0oC can a freezer make into ice cubes in 1.0 hour, if the coefficient of performance of the cooling unit is 7.0 and the power input is 1.0 kilowatt?
2. C.O.P.=QL/W
Q=mlfusion
\rho=m/v
3. I found QL by using the above formula, which gave me 700J. Next I used Q=ml (l=333000j/kg) to find the mass which is where I got .002 kg (I'm pretty sure that this is where I made my mistake.) Next I know to use the formula for density to divide the mass by the density of water (1 x 103. Can somebody point out where I made a mistake, or if my thinking is wrong?
 
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How do you 700J for QL ? Shouldn't it be 7J.
 
How many J/s are in 1 KW?
 
Sorry, I figured out the problem (1000J/s in 1 KW instead of 100...,) but don't know how to close the thread (if possible.) Thanks for the responses though!
 
Only Administrators can close threads, so don't worry.
 
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