You are given Q and you can determine [itex]\Delta U = nC_v\Delta T[/itex]. So it is just a matter of applying the first law to determine W.Robershky said:Homework Statement
When 1380 J of heat are added to one mole of an ideal monatomic gas, its temperature increases from 272 K to 275 K. Find the work done by the gas during this process.
Homework Equations
I assume [tex]\Delta[/tex]U = Q - W is the formula to use. But for some reason I'm just confused.
The Attempt at a Solution
I tried using 1380 = 275 - W, and got -1105. But that is not the correct answer.
To calculate work using thermodynamics, you will need to use the formula W = Q - ΔU, where W represents work, Q represents heat, and ΔU represents the change in internal energy. This formula takes into account energy conservation and allows you to find work given heat and a change in temperature.
The unit of measurement for work in thermodynamics is joules (J). This is the same unit used to measure heat and energy in the metric system. In some cases, other units such as kilojoules (kJ) or calories (cal) may be used, but they can easily be converted to joules.
No, the formula W = Q - ΔU can only be used to calculate work in isothermal processes, where the temperature remains constant. For other processes such as adiabatic or isobaric, different formulas must be used. It's important to understand the specific conditions of the process in order to use the correct formula.
The direction of work is determined by the sign of the calculated value. A positive value for work indicates that work is being done on the system, while a negative value indicates that work is being done by the system. This is consistent with the first law of thermodynamics, which states that energy cannot be created or destroyed, only transferred or converted.
Calculating work in thermodynamics allows us to understand and quantify the energy changes that occur in a system. This is important for many industrial and engineering applications, as well as for understanding the behavior of gases and other materials. It also allows us to predict and control the efficiency of heat engines and other energy conversion processes.