Thermodynamics: Solving for Initial Temperature of Copper in Ethanol Solution

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The discussion revolves around a calorimetry problem involving the heat exchange between aluminum, copper, and ethanol. The initial temperatures and specific heat capacities are used to calculate the heat transfer, with the final temperature of the system being 28 degrees Celsius. Participants suggest balancing the heat lost by aluminum and copper with the heat gained by ethanol to find the initial temperature of copper. The calculations for the heat transfer for each component are being performed, and the approach appears to be on the right track. Overall, the focus is on applying the correct thermodynamic equations to solve for the unknown initial temperature of copper.
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Homework Statement


11 grams of Aluminium at 200 degrees Celsius and 19 grans of Copper are dropped into 49 cubic centimetres of ethanol at 15 Degrees Celsius, The temperature Quickly becomes 28 Deegres Celsuis.

What was the initial temperature of copper?

Homework Equations



Q= c dT

The Attempt at a Solution



I am very lost.. please help
 
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This is a calorimetry problem.

Cast your formula in the following form: Q = m cp (Tf - To). Balance heat loss and heat gained by all the components. And note all materials will have the same Tf.
 
ok so what i did was to find Q value for Ethanol and Aluminium

Ethanol density = .79 g/ cm3 in 49 cm3 = 0.0387 kg
Q Al = 0.011kg * (900 J /kg K) * (473.15K - 301.15K)
Q Eth= 0.0387kg (2400J/kg K) * (301.15K- 288.15K)
Q Cu = 0.019kg * (385 j /Kg K) * (301.15 - ?)

am I going well ?
 
Looks good so far.
 
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