Thermodynamics: Water Properties

[engineering lord]

Homework Statement

Two pans filled with water. Water in a 3.7cm deep pan is observed to boil at 98 degrees celsius. At what temperature will the water in a 46.3cm deep pan boil?

Homework Equations

P=3.146T-211.87 (linear approximation)
Water properties table:
95°C 84.609kPa .001060 vf 1.9808vg
100°C 101.42kPa .001043vf 1.6720vg

The Attempt at a Solution

I set the linear approximation equal to the equation P=ρh so I have ρ(.037m)=3.146*98-211.87 to solve for density. Now I have density, but I am stuck. How can I find the temperature of boiling with only the density? I can find the reciprocal, ν, but how does that allude to the temperature?

 

[Chestermiller]

What is the change in pressure between 3.7 cm depth and 46.3 cm depth if the density is about 1.043 gm/cm^3?