Find Rth in Thevenen Equivalent Circuit: R1,R2,R3,R4,R5,R6,Vth

AI Thread Summary
The discussion focuses on finding the Thevenin equivalent circuit with R5 as the load, given specific voltage and resistance values. The initial calculation for Vth was -5V, but after further analysis, a new value of approximately 3.72V was derived. The participants confirmed the correct approach to calculating Rth and discussed the impact of replacing the current source with a voltage source. The final consensus indicates that the calculations align, and the polarity of the voltage source is correctly identified. Overall, the thread emphasizes the importance of accurate circuit analysis for exam preparation.
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[PLAIN]http://img695.imageshack.us/img695/2420/physicsm.jpg

i need to find thevenen equivalent circuit using R5 as load

Ε1=20V, Ε2=10V, R1=6Ω, R2=12Ω, R3= 25Ω, R4=20Ω,
R5=10Ω, R6=5Ω, Ι=0,2Α.

Vth = -5V


but how much is Rth?

i can see that R4 is in series with (R2+R1)||R3 and R6

is this correct?

so the circuit will be

[PLAIN]http://img37.imageshack.us/img37/9126/62188572.jpg

please tell me if I am correct or not i need to know for the exams :(
 
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Your calculation for Rth is correct, but I got a different value for Vth.
 
vela said:
Your calculation for Rth is correct, but I got a different value for Vth.

i replaced the current source with a voltage source

we have no current on teh second loop

so the voltage source has 5V

hence-E2 + 5V = -5V will be the Vth

am i doing anything wrong?

oh but we have current going through the voltage source

so i have to find the current in the first loop

E1 - E3 - I*(R1+R2+R3) = 0

I = 15/43 = 0.348837209 A

so Vth = -5 + (0.348837209*R3) = -5 + 8.72093023 = 3.72093023 V

is this correct?

so in the shape the + will be on top and - on bottom
 
Last edited:
Yes, that matches what I calculated.
 
thanks a lot for your help :))
 
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