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Find the equivalent resistance of a circuit below

  1. Jul 29, 2012 #1
    Find the equivalent resistance of the circuit shown below. Each of the six resistors has a resistance of 12 ohm.
    physics.jpg

    I just want to make sure I calculated everything right. I don't have the solution available.

    Labelling the resistors from my left to the right: R1, R2, R3, R4, R5(bottom), R6

    What I did:

    R5 + R6 = R56

    1/R56 + 1/R4 = R456

    R456 + R3 = R3456

    1/R3456 + 1/R2 = R23456

    R23456 + R1 = Req = 20Ω

    Thanks!
    1. The problem statement, all variables and given/known data



    2. Relevant equations



    3. The attempt at a solution
     
  2. jcsd
  3. Jul 29, 2012 #2
    Your logic all looks correct to me. I don't have a calculator available, but your work looks fine and the answer seems reasonable.

    Edit: The post below me is correct, I missed those errors.
     
    Last edited: Jul 30, 2012
  4. Jul 29, 2012 #3
    No, 1/R56 + 1/R4 = 1/R456


    No, 1/R3456 + 1/R2 = 1/R23456
     
  5. Jul 29, 2012 #4
    The resistors are of equal value.
    In calculation this value is substituted in the equations.
    R5+R6=2R
    Next the parallel resistor
    2R.R/(2R+R)=2R/3
    And the next configuration till R1
     
  6. Jul 30, 2012 #5
    Thanks guys!
     
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