Find the equivalent resistance of a circuit below

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Homework Help Overview

The discussion revolves around finding the equivalent resistance of a circuit containing six resistors, each with a resistance of 12 ohms. Participants are verifying calculations and discussing the setup of the circuit.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to calculate the equivalent resistance step-by-step, while others question the accuracy of the mathematical expressions used in the calculations.

Discussion Status

Some participants have provided feedback on the calculations, with one confirming the logic appears correct, while another points out errors in the mathematical notation. The discussion is ongoing, with multiple interpretations of the calculations being explored.

Contextual Notes

Participants are working under the assumption that all resistors have the same value, and there is a lack of access to calculators for verification of the computations.

shashaeee
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Find the equivalent resistance of the circuit shown below. Each of the six resistors has a resistance of 12 ohm.
physics.jpg


I just want to make sure I calculated everything right. I don't have the solution available.

Labelling the resistors from my left to the right: R1, R2, R3, R4, R5(bottom), R6

What I did:

R5 + R6 = R56

1/R56 + 1/R4 = R456

R456 + R3 = R3456

1/R3456 + 1/R2 = R23456

R23456 + R1 = Req = 20Ω

Thanks!
 
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Your logic all looks correct to me. I don't have a calculator available, but your work looks fine and the answer seems reasonable.

Edit: The post below me is correct, I missed those errors.
 
Last edited:
shashaeee said:
1/R56 + 1/R4 = R456

No, 1/R56 + 1/R4 = 1/R456


1/R3456 + 1/R2 = R23456

No, 1/R3456 + 1/R2 = 1/R23456
 
The resistors are of equal value.
In calculation this value is substituted in the equations.
R5+R6=2R
Next the parallel resistor
2R.R/(2R+R)=2R/3
And the next configuration till R1
 
Thanks guys!
 

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