Third order Euler Differential Equation

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Homework Statement


x^3y'''-3x^2y''+7xy'-8y=x+e^2x

Edit : Got it thanks
 
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hunt_mat said:
Have you thought about trying the solution [tex]y=x^{n}[/tex]? This might lead to an easier cubic to solve.

Not sure how that would work out, only told to use t=lnx. But using [tex]y=x^{n}[/tex] won't cancel the coefficients to be constants.

Edit: I looked up your response on Wikipedia and found something similar on it, never learned to do it this way tho. I'll give it a shot.
 
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They will add up to give [tex]x^{n}[/tex] though. for example if y=x^n, then x^{3}y'''(x)=n(n-1)(n-2)x^n, likewise for x^2 and so on. I calculate that the cubic you arrive at the cubic:
[tex] n^{3}-6n^{2}+12n-8[/tex]
One of the solutions look to be n=2.

Mat
 
hunt_mat said:
They will add up to give [tex]x^{n}[/tex] though. for example if y=x^n, then x^{3}y'''(x)=n(n-1)(n-2)x^n, likewise for x^2 and so on. I calculate that the cubic you arrive at the cubic:
[tex] n^{3}-6n^{2}+12n-8[/tex]
One of the solutions look to be n=2.

Mat

Got it thanks.