This integral is just whooping my butt

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Homework Statement



General antiderivative of:

e^(sqrt(2x) + 3)

Homework Equations





The Attempt at a Solution



http://imageshack.us/photo/my-images/171/integralm.png/

I have no idea what to do, my process is chaotic. I arrive at an answer but it doesn't seem to agree with the book.
 
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Your answer looks correct, though the book answer would probably factor it: (\sqrt{2x}-1)\exp(\sqrt{2x}+3). Is that what the difference is?

As to your method, you could just make one substitution, y = \sqrt{2x}, rather than making two.
 
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...
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