This magnet question confounds me

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The discussion revolves around a physics problem concerning the relationship between the magnetic field (B-field) and the radius (R) of a charged particle's circular motion. The participants debated between two graph choices: a straight line with a negative slope (Choice H) and a hyperbolic graph (Choice J). The correct relationship derived from the equations shows that as the B-field increases, the radius decreases, leading to the conclusion that the graph representing this relationship is hyperbolic (Choice J). The term "Larmor Radius" is mentioned, indicating the established concept related to this phenomenon. The final consensus supports that the hyperbolic graph accurately depicts the inverse relationship between B-field and radius.
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Homework Statement


Today, my teacher gave us some practice AP multiple choice and my friend and I were debating between answer choices H and J (changed from A and B to remove any confusion) the question as i remember it:
blah blah... B-field into the page, constant velocity v, radius R and charge q. which graph shows the relationship between B-field and radius.. something with radius getting smaller as B-field gets larger

Choice H: this is a straight line coming from +y crossing the +x axis (basically a straight negative slope)

Choice J: the (1/x) graph with x>0



Homework Equations


Fc = mv^2/r
Fb= qvB


The Attempt at a Solution



Fc=Fb
\frac{mv^2}{r}=qvB
\frac{mv}{r}=qB
since mv and q are constants, is it ok to treat them as 1? that is what i did so...

\frac{1}{r}=B
\frac{1}{B}=r

since on the graphs r was the y-axis and B was the x-axis

i chose the (1/x) shaped graph
 
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lodovico said:

Homework Statement


Today, my teacher gave us some practice AP multiple choice and my friend and I were debating between answer choices H and J (changed from A and B to remove any confusion) the question as i remember it:
blah blah... B-field into the page, constant velocity v, radius R and charge q. which graph shows the relationship between B-field and radius.. something with radius getting smaller as B-field gets larger

Choice H: this is a straight line coming from +y crossing the +x axis (basically a straight negative slope)

Choice J: the (1/x) graph with x>0



Homework Equations


Fc = mv^2/r
Fb= qvB


The Attempt at a Solution



Fc=Fb
\frac{mv^2}{r}=qvB
\frac{mv}{r}=qB
since mv and q are constants, is it ok to treat them as 1? that is what i did so...

\frac{1}{r}=B
\frac{1}{B}=r

since on the graphs r was the y-axis and B was the x-axis

i chose the (1/x) shaped graph


Yes, it is known as the Lamor Radius:

http://www-fusion.ciemat.es/fusionwiki/index.php/Larmor_radius

:smile:
 
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