This problem has to do with mass and time

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AI Thread Summary
The problem involves determining the maximum mass of water in a leaking container, described by the function m=5.00(t)^0.8 - 3.00t + 20.00. To find the time when the mass is greatest, optimization techniques from calculus are required, specifically identifying the maximum of the function. The maximum mass occurs at 4 seconds, which allows for further calculations. Additionally, the rate of change of mass at specific times (t=2.00 s and t=5.00 s) can be derived from the function's derivative. Understanding this optimization process is key to solving the problem effectively.
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Homework Statement


Water is poured into a container that has a leak. The mass m of the water is given as a function of time t by m=5.00(t)^.8- 3.00t+ 20.00. with t being greater or equal to zero, m in grams, and t in seconds. (a) at what time is the water mass greatest (b) what is the greatest mass? in kilograms per minute, what is the rate of change at (c) t=2.00 s and (d) t=5.00s


how do i do this probelm

Homework Equations


what equations can i use


The Attempt at a Solution



if i knew what to do or sort of do i could attempt it
 
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is question a asking me to plug in a time that will allow the equation to equal to zero
 
This is a problem in optimisation using calculus. Think of how to find the max and min of a function. That's all you need to do this problem, no physics involved.
 
I figured it out. It was 4 seconds for question (a) and that opened up the rest of the problems.
 
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...

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