Three bys trying to balance a seesaw

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    Balance Seesaw
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To balance the seesaw with three boys, the principle of moments must be applied, where the sum of the moments on one side equals the sum on the other. The first two boys have masses of 53.0 kg and 32.8 kg, positioned at either end of the 3.52 m seesaw. The third boy, weighing 23.0 kg, needs to find his position from the center to achieve equilibrium. The calculation involves adding the moment created by the third boy to the existing moments from the first two boys. Posting the work done can help others provide assistance in solving the problem.
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Three boys are trying to balance on a seesaw, which consists of a fulcrum rock, acting as a pivot at the center, and a very light board L = 3.52 m long, see figure below.

Two boys are already on either end. One has a mass of m1 = 53.0 kg, and the other a mass of m2 = 32.8 kg. How far from the center should the third boy, whose mass is m3 = 23.0 kg, place himself so as to balance the seesaw?

i know how to do it but with just to boys, but with three boys idont have the minimum idea... can anyone helps me?...
 
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Naldo6 said:
Three boys are trying to balance on a seesaw, which consists of a fulcrum rock, acting as a pivot at the center, and a very light board L = 3.52 m long, see figure below.

Two boys are already on either end. One has a mass of m1 = 53.0 kg, and the other a mass of m2 = 32.8 kg. How far from the center should the third boy, whose mass is m3 = 23.0 kg, place himself so as to balance the seesaw?

i know how to do it but with just to boys, but with three boys idont have the minimum idea... can anyone helps me?...

Solving the problem with two boys and three boys is done exactly the same way--there is just one more term in your equation. So try doing it the same way, and if you get stuck, please post your work so that we can help you.
 
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