Fromasdf1 said:where does t`=(t-vx/c^2)/(1-v^2/c^2)^1/2 come from?
There are many elegant ways to derive the Lorentz transformation:asdf1 said:where does t`=(t-vx/c^2)/(1-v^2/c^2)^1/2 come from?
Or rather they should both be [tex]-\sinh(\theta)[/tex] I believe.robphy said:It should be [tex]+\sinh(\theta)[/tex].
(The determinant has to be 1.)
Yes, of course :tongue2: , considering the original post. Thanks.learningphysics said:Or rather they should both be [tex]-\sinh(\theta)[/tex] I believe.