- #1
Huumah
- 27
- 0
Can anyone help my to see why my solution is wrong because the in the solutions it says that it is not time invariant
Time Invariant Signal: Help Me See Why My Solution is Wrong
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SUMMARY
The discussion centers on the concept of time invariance in signal processing, specifically addressing a user's confusion regarding their solution's validity. The user presents a simple example where y(0) = x(-2) + x(2) and y(1) = x(-1) + x(1), questioning why this solution is deemed not time invariant. The consensus indicates that the sums can indeed differ based on the input signal, leading to the conclusion that the system described is not time invariant.
PREREQUISITES- Understanding of time invariance in signal processing
- Familiarity with discrete-time signals
- Knowledge of signal transformations
- Basic mathematical operations involving functions
- Study the principles of time invariance in linear systems
- Learn about discrete-time signal representation
- Explore examples of time-invariant and time-variant systems
- Investigate the implications of signal transformations on system behavior
Students and professionals in electrical engineering, signal processing enthusiasts, and anyone seeking to deepen their understanding of time invariance in systems.
Can anyone help my to see why my solution is wrong because the in the solutions it says that it is not time invariant
- #2
mfb
Mentor
- 37,445
- 14,313
I don't understand what y_A and y_B are.
Simple example:
y(0)=x(-2)+x(2)
y(1)=x(-1)+x(1)
In general, those sums can be different.
Simple example:
y(0)=x(-2)+x(2)
y(1)=x(-1)+x(1)
In general, those sums can be different.
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