Time it takes for light to travel 54 cm

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To calculate the time it takes for light to travel 54 cm through glycerin with an index of refraction of 1.470 at 20˚C, the speed of light in glycerin must be determined. The correct speed is calculated using the formula for the speed of light in a medium, which is the speed of light in vacuum divided by the refractive index. The initial attempt incorrectly used a formula for the speed of sound, leading to an erroneous time calculation of 0.0015752 seconds. The correct answer for the time taken is approximately 2.626 x 10^-9 seconds, highlighting the importance of using the appropriate equations for light rather than sound. Understanding the refractive index is crucial for accurate calculations in optics.
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Homework Statement



How do you find the time it takes for light to travel 54 cm through glycerin (index of refraction = 1.470 at 20˚C) in an aquarium?

Homework Equations



These equations might be useful: v= 331 m/s + (0.59 m/s/c˚)(T) niSinθi=nRSinθR

The Attempt at a Solution



v= 331 m/s + (0.59 m/s/c˚)(20˚C)
v= 331 m/s + 11.8 m/s
v= 342.8 m/s

Δt= 0.54 m ÷ 342.8 m/s = 0.0015752 s

But this isn't the right answer
 
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Your problem says "1.470 at 20˚C" which I would interpret to mean that the speed of light in glycerin, at 20˚C, is 1.470 times the speed in vacuum- which would mean that, since you problem asks about the time at 20 C˚, there would be NO correction for temperature.
That is, the speed of light in glycerine, at 20˚C is just the speed of light in vacuum times 1.47.

If I am misinterpreting that, then what is the "0" point for T? 0˚Celcius or (more common) 0˚Kelvin?
 
1. Homework Statement

How do you find the time it takes for light to travel 54 cm through glycerin (index of refraction = 1.470 at 20˚C) in an aquarium?

2. Homework Equations

These equations might be useful: v= 331 m/s + (0.59 m/s/c˚)(T) niSinθi=nRSinθR

3. The Attempt at a Solution

v= 331 m/s + (0.59 m/s/c˚)(20˚C)
v= 331 m/s + 11.8 m/s
v= 342.8 m/s

Δt= 0.54 m ÷ 342.8 m/s = 0.0015752 s

But this isn't the right answer
 
is the answer : 2.626 x 10^-9 ?
 
cupid.callin said:
is the answer : 2.626 x 10^-9 ?

yes! can you show me how to do it!
 
well i didnt use your first eqn

i used: refractive index = (velocity of light in vacuum = 3 x 10^8) / (velocity of light in vaccum)

find velocity in glycerin and use d=vt
 
crystalspark said:
[
These equations might be useful: v= 331 m/s + (0.59 m/s/c˚)(T)

That formula might refer to the speed of sound in air.

ehild
 
cupid.callin said:
is the answer : 2.626 x 10^-9 ?

Please do not give answers to homework questions. That is against the PF Rules (see the link at the top of the page).
 
crystalspark said:
1. Homework Statement

How do you find the time it takes for light to travel 54 cm through glycerin (index of refraction = 1.470 at 20˚C) in an aquarium?

2. Homework Equations

These equations might be useful: v= 331 m/s + (0.59 m/s/c˚)(T) niSinθi=nRSinθR

3. The Attempt at a Solution

v= 331 m/s + (0.59 m/s/c˚)(20˚C)
v= 331 m/s + 11.8 m/s
v= 342.8 m/s

Δt= 0.54 m ÷ 342.8 m/s = 0.0015752 s

But this isn't the right answer

Duplicate threads merged. Please take care not to multiple post.
 
  • #10
OH YES! That eqn is for sound!
 
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