Titration Help: Standardize HCl Using Oxalic Acid & CaCOH Solution

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To prepare a standard solution of oxalic acid at approximately 0.05M, calculate the required mass using the formula: mass = molarity × volume × molar mass. For a 250 ml volumetric flask, this involves determining the moles needed and converting it to grams. Oxalic acid, being a diprotic acid, will require half the amount of moles to neutralize the base in the titration process. The solution of CaCOH can then be analyzed using this standard solution to find its concentration, which will subsequently allow for the standardization of the HCl solution. During the lab, attention to detail is crucial, particularly in measuring and transferring solutions, as inaccuracies can affect results. Despite some challenges with technique, successful completion of the calculations indicates a solid understanding of the process.
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Prepare a standard solution of oxalic acid (approx. 0.05M). Use it to find the conc of the given solution of CaCOH. Use this to standardize the given solution of HCl.

So basically I am suppose to do this as an inclass lab. I will be given a 250 ml volumetric flask where i will have to mix water and a calculated amount of oxalic acid in solid form in it. How will I do the calculations and how will I approach this lab. I'm so lost. Any help would great, thanks in advance!
 
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Any textbook on analytical chemistry covers alkalimetric titration, together with precise recipes and how-tos.
 
Dynamis said:
Question:
Prepare a standard solution of oxalic acid (approx. 0.05M). Use it to find the conc of the given solution of CaCOH. Use this to standardize the given solution of HCl.

So basically I am suppose to do this as an inclass lab. I will be given a 250 ml volumetric flask where i will have to mix water and a calculated amount of oxalic acid in solid form in it. How will I do the calculations and how will I approach this lab. I'm so lost. Any help would great, thanks in advance!

keep in mind that oxalic acid is a diprotic acid, so it will take half the amount of oxalic acid (moles) to neutralize all of the base.
 
Thanks for the response guys, I did pretty good on this inclass lab exam today, as far as the calculations went, but the actual titrating and stuff was a little weird as I overfilled my volumetric flask and some other weird stuff. Overall I did alright, but thanks anyway for the help.
 
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