Torque acting on a movable dielectric

  • Thread starter Thread starter Wavefunction
  • Start date Start date
  • Tags Tags
    Dielectric Torque
Wavefunction
Messages
99
Reaction score
4

Homework Statement


parallel-plate capacitor consists of two fixed metal semicircles of radius R and a
dielectric plate (susceptibility \varepsilon). The plate is able to rotate without friction around the
axis centered at the point O (axis O is perpendicular to the picture). Plate's thickness is h and the plate is filling all the space between capacitor plates. Constant potential difference V is applied to the capacitor. Find the torque \tau acting on the movable dielectric
plate when it is tilted by the angle \alpha as shown on the picture.

Homework Equations



\mathbf{\tau}=\mathbf{p}\times\mathbf{E}

The Attempt at a Solution



I'm not too sure where to begin on this one, but here's what I think is physically going on: Since the dielectric is not completely within the two capacitors, there is a fringe field which is not parallel to the polarization of the dielectric material which is thus creating a torque on the dielectric.
 
Physics news on Phys.org
Thanks for the post! Sorry you aren't generating responses at the moment. Do you have any further information, come to any new conclusions or is it possible to reword the post?
 
It's okay I have actually solved the question: it was suggested to me by my quantum mechanics TA to view this as a capacitor whose capacitance changes when alpha changes. Then you can use the energy stored in the capacitor and differentiate with respect to alpha in order get the torque :) . Thank you for the response though! Cheers
 
Thread 'Need help understanding this figure on energy levels'
This figure is from "Introduction to Quantum Mechanics" by Griffiths (3rd edition). It is available to download. It is from page 142. I am hoping the usual people on this site will give me a hand understanding what is going on in the figure. After the equation (4.50) it says "It is customary to introduce the principal quantum number, ##n##, which simply orders the allowed energies, starting with 1 for the ground state. (see the figure)" I still don't understand the figure :( Here is...
Thread 'Understanding how to "tack on" the time wiggle factor'
The last problem I posted on QM made it into advanced homework help, that is why I am putting it here. I am sorry for any hassle imposed on the moderators by myself. Part (a) is quite easy. We get $$\sigma_1 = 2\lambda, \mathbf{v}_1 = \begin{pmatrix} 0 \\ 0 \\ 1 \end{pmatrix} \sigma_2 = \lambda, \mathbf{v}_2 = \begin{pmatrix} 1/\sqrt{2} \\ 1/\sqrt{2} \\ 0 \end{pmatrix} \sigma_3 = -\lambda, \mathbf{v}_3 = \begin{pmatrix} 1/\sqrt{2} \\ -1/\sqrt{2} \\ 0 \end{pmatrix} $$ There are two ways...
Back
Top