Torque and center of mass question

AI Thread Summary
The discussion focuses on calculating the center of mass of a block with non-uniform density suspended by two massless wires at angles phi_1 and phi_2. The participant has derived the forces and torques acting on the block, equating them to find the center of mass. However, their calculated position for the center of mass, x = (L sin(phi_2)) / (sin(phi_1) + sin(phi_2)), is deemed incorrect, prompting a review of their trigonometric calculations. Clarification is provided that the wires are attached to the ends of the block, with one wire on the left and the other on the right. The participant is encouraged to reassess their fulcrum placement and trigonometric functions to resolve the issue.
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We have a block of un-uniform density of mass m suspended by two massless wires, against gravity. The left wire makes an angle phi_1while the right angle makes an angle phi_2. The block has length L. They want me to find the center of mass.
THis is what I've done:
We have tension in the wires. Torque is force measured from a distance. In our case, the two wires create a torque about the center of mass. I find the forces,
F_1 = sin(phi_1)*m*g
F_2 = sin(phi_2)*m*g
And realize that the torques are
t_1 = F_1*x_c_m;
t_2 = F_2*(L - x_c_m)
since they equal another (net torque is zero), i set them t_1 = t_2 and solve for x. However the answer is incorrect and I am told to check my trignometry. My answer is
x = (L sin(phi_2)) / (sin(phi_1)+sin(phi_2))

whatever am i doing wrong?
 
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Where do you put your fulcrum?
 
my fulcrum is x_cm, or the center of mass of the block from the left side.
 
One question... are the wires attached to the ends of the block, you were not clear on that...
 
yes they are. the wire making an angle phi_1 is on the left side and the wire making an angle phi_2 is on the right side.
 
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